1.

The following numbers, K + 3, K + 2, 3K – 7 and 2K – 3 are in proportion. Find K.

Answer»

Here, (K + 3/K + 2) = (3k - 7/2k - 3)

⇒ (K + 3) (2K – 3) = (K + 2) (3K – 7). 

⇒ 2K2 – 3K + 6K – 9 = 3K2 – 7K + 6K – 14 

⇒ K2 – 4K – 5 = 0 ⇒ (K – 5) (K + 1) = 0 

⇒ K = 5 or K = – 1



Discussion

No Comment Found

Related InterviewSolutions