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The following observations were made in an experiment with Poiseuille's apparatus: Diameter of tube = 0.1 cm Density of liquid=2.4 g/cm""^(3) Volume of liquid collected per minute = 10 cm^(3) Pressure head of liquid = 25 cm Length of tube = 20 cm Using the above data, calculate the viscosity of the liquid. |
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Answer» SOLUTION :The volume Q of liquid flowing out per second through the capillary tube is `Q=(pi Pr^(4))/(8 eta l)` where `P/l` is the pressure gradient r is the radius of the tube `eta ` is the viscosity Given, `Q =10 CM^(3)" per MINUTE "= 10/60 cm^(3)` per s `P=hpg =25 xx 2.4 xx 980` l=20 cm `r=(0.1 cm)/(2)=0.05 cm` `n=?` `eta=(pi Pr^(4))/(8 l Q)` `=(3.14 xx 25 xx 2.4 980 xx (0.05)^(4) xx 60)/(8 xx 20 xx 10)` =0.043 cgs unit |
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