1.

The following observations were made in an experiment with Poiseuille's apparatus: Diameter of tube = 0.1 cm Density of liquid=2.4 g/cm""^(3) Volume of liquid collected per minute = 10 cm^(3) Pressure head of liquid = 25 cm Length of tube = 20 cm Using the above data, calculate the viscosity of the liquid.

Answer»

SOLUTION :The volume Q of liquid flowing out per second through the capillary tube is
`Q=(pi Pr^(4))/(8 eta l)`
where `P/l` is the pressure gradient
r is the radius of the tube
`eta ` is the viscosity
Given, `Q =10 CM^(3)" per MINUTE "= 10/60 cm^(3)` per s
`P=hpg =25 xx 2.4 xx 980`
l=20 cm
`r=(0.1 cm)/(2)=0.05 cm`
`n=?`
`eta=(pi Pr^(4))/(8 l Q)`
`=(3.14 xx 25 xx 2.4 980 xx (0.05)^(4) xx 60)/(8 xx 20 xx 10)`
=0.043 cgs unit


Discussion

No Comment Found