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The following table shows the distance travelled by a freely falling body and the time taken.Time (t)1 second2 seconds3 seconds........Distance (s)1 x 4.9 m4 x 4.9 m9 × 4.9 m........(a) What is the time taken by it to travel 16 x 4.9 meter ?(b) How much distance does it travel in 10 seconds ?(c) Write the relation between ‘s’ and ‘t’ as an equation.(d) Which measure are in proportion ? What is the constant of proportionality ? |
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Answer» On observing data (a) When s = 16 x 4.9 m ∴16 x 4.9 = 4.9 x t2 ∴ t2 = 16 t = 4 sec (b) When t = 10 s = 4.9 x t2 = 4.9 x (10)2 s = 490 m (c) s ∝ t2 s = kt2 where k = 4.9 m/sec2 (d) Distance is proportional to the square of time taken to the freely falling body constant of proportionality is 4.9 m/sec2. |
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