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The following velocity-time graph represents a particle moving in the positive x-direction . Analyse itsmotion from 0 to 7s . Calculate the displacement covered and distance travelled by the particle from 0 to 2s |
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Answer» Solution :GIVEN : t = 2s Formula : Area of triangle ` = (1)/(2) xx l xx b` = displacement In the graph 0 to 2s is divided into 2 triangle , Case I :t = 0 to 1 . 5 s Area ` =(1)/(2) xx (1.5) xx 2 = 1.5` Case II : t = 1 . 5 to 2s Area ` =(1)/(2) xx (0.5) xx 1 = (0.5)/(2)` = 0 . 25 `:.`Distance= 1.5 + 0 . 25 = 1.75 m Displacement= 0 . 25 - 1.5 = - 1.25 m |
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