InterviewSolution
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InterviewSolution
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The force acting on a window of are 50`xx`50 cm of a submarine at a depth of 2000 m in an ocean ,the interior of which is maintained at sea level atmospheric pressure is (density of sea water = `10 ^(3) kg m^(-3)` ,g =`10 m s^(-2)` )A. `5 xx10^(5)N`B. `25 xx10^(5)` NC. `5 xx 10^(6)`ND. `25 xx 10^(6)`N |
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Answer» Correct Answer - C Here, h=2000 m, `rho=10^(3) kg m^(-3), g=10 m s^(-2)` The pressure outside the submarine is `P=P_(a)+rhogh` where `P_(a)` is the atmospheric pressure. Pressure inside the submarine is `P_(a)` . Hence, net pressure acting on the window is gauge pressure. Gauge pressure, `P_(g)=P-P_(a)=rhogh` `=10^(3) kg m^(-3) xx 10 m s^(-2)xx 2000 m=2xx10^(7)` Pa Area of a window is `A=50 cm xx50 cm = 2500 xx 10^(-4) m^(2)` Force acting on the window is `F=P_(g)A` `=2xx10^(7)Pa xx 2500xx10^(-4) m^(2)=5xx10^(6)N` |
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