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The force of attraction between two charges separated by certain distance in air is `F_(1)` .If the space between the charges is completely filled with dielectric of constant `4` the force becomes `F_(2)` .If half of the distance between the charges is filled with same dielectric the force between the charges is `F_(3)` Then `F_(1):F_(2):F_(3)` isA. `16:9:4`B. `9:36:4`C. `4:1:2`D. `36:9:16` |
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Answer» Correct Answer - 4 `F=(1)/(4piepsilon_(0)epsilon_(r))(q_(1)q_(2))/(d^(2))` |
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