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The force required to punch a hole of diameter 2 mm, will be (If a shearing stress `4xx10^(8)N//m^(2)`.)A. `400pi N`B. `1600 pi N`C. `1800pi N `D. `1200pi N` |
Answer» Correct Answer - A Stress `=(F)/(A)` `therefore F= "Stress" xx pi r^(2)` |
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