1.

The formula of rust can be represented by Fe_(2)O_(3). How many mole of Fe are present in 16 gm of rust.

Answer»

0.1
0.2
0.4
0.3

Solution :16 GM rust `RARR(16)/(160)` MOLES of rust
0.1mole of rust
moles of `Fe=2xx("molar of rust")`
`=2xx0.1=0.2`


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