Saved Bookmarks
| 1. |
The formula of rust can be represented by `Fe_(2)O_(3)`. How many mole of Fe are present in 16 gm of rust.A. 0.1B. 0.2C. 0.4D. 0.3 |
|
Answer» 16 gm rust `rArr(16)/(160)` moles of rust 0.1mole of rust moles of `Fe=2xx("molar of rust")` `=2xx0.1=0.2` |
|