1.

The formula of rust can be represented by `Fe_(2)O_(3)`. How many mole of Fe are present in 16 gm of rust.A. 0.1B. 0.2C. 0.4D. 0.3

Answer» 16 gm rust `rArr(16)/(160)` moles of rust
0.1mole of rust
moles of `Fe=2xx("molar of rust")`
`=2xx0.1=0.2`


Discussion

No Comment Found

Related InterviewSolutions