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The formula weight of an acid is 82.0. In a titration, 100cm^(3) of a solution of this acid containing 39.0 g of the acid per litre were completely neutralised by 95.0cm^(3 of aqueous NaOH containing 40.0 of g NaOH per litre. What is the basicity of the acid? |
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Answer» Solution :Suppose the equivalent wt. of the acid = E `therefore"Normality of the acid solution"=(39gL^(-1))/(E)` EQ. wt. of NaOH = 40 `therefore"Normality of NaOH solution"=(40gL^(-1))/(40)=1N` `"Applying"underset("(Acid)")(N_(1)xxV_(1))=underset("(NaOH)")(N_(2)xxV_(2))` `(39)/(E)xx100=1xx95 or E=41.0` `"Basicity of the acid"=("Formula wt.")/("Equivalent wt.")=(82.0)/(41.0)=2` |
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