1.

The formula weight of an acid is 82. In a titration, 100 cm^(3) of a solution of this acid containing 39.0 g of the acid per litre were completely neutralised by 95.0 cm^(3) of aqueous NaOH containing 40.0 g of NaOH per litre. What is the basicity of the acid ?

Answer»


Solution :NORMALITY of NaOH=1
Normality of acid `=(1xx95)/(100)=0.95`
LET the eq. MASS of the acid be E.
`therefore (39)/(E )=0.95 " or " E=41, "" "Basicity"=(82)/(41)=2`


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