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The formulation of polyethene from calcium carbide takes place as follows: `CaC_2+2H_2OtoCa(OH)_2+C_2H_2` `C_2H_2+H_2toC_2H_6` `nC_2H_6to-(CH_2-CH_2)-_n` The amount of polythene obtained from 64 kg of `CaC_2` isA. 7 kgB. 14 kgC. 21 kgD. 28 kg

Answer» Correct Answer - D
64 kg of `CaC_2` corresponds to `10^(3)` mol of `CaC_2` according to the given equation 1 mol of `CaC_2` yields 1 mol of `C_2H_4`. Thus, `10^(3)` mol of `CaC_2` will yield `10^(3)` mol of `C_2H_4` having the mass 28 kg Since during the process of polymerization, mass is conserved the amount of polyethene produced will also be 28kg.


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