The forward characteristic curve of a junction diode is shown in Figur – InterviewSolution

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1.

The forward characteristic curve of a junction diode is shown in Figure belowCalculate the resistance of the diode a :(1) c = 0.5 v(2) I = 60 mA

Answer»

(1) R = \(\frac{V}{I}=\frac{0.5}{40\times10^{-3}}\) = \(\frac{500}{40}\) = 12.5 Ω

(2) R = \(\frac{V}{I}=\frac{0.6}{60\times10^{-3}}\) = \(\frac{600}{60}\) = 10.0 Ω

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