1.

The four quantum number of the outermost orbital of K (atomic no. =19) are

Answer»

n=2,l=0, m=0, `s= + 1/2`
n=4,l=0, m=0, `s= + 1/2`
n=3,l=1, m=1, `s= + 1/2`
n=4,l=2, m=-1, `s= + 1/2`

SOLUTION :`K_19=1s^2 ,2s^2 2p^6 , 3s^2 3p^6 ,4s^1`
for `4s^1` ELECTRONS.
n=4, l=0, m=0 and `s=+1/2`


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