The fraction of the total volume occupied by the atoms present in a si

1.	The fraction of the total volume occupied by the atoms present in a simple cube is
Answer» `PI/4` `pi/6` `pi/(3sqrt2)` `pi/(4sqrt2)` Solution :In a simple CUBE, no. of atoms/unit cell ` = 8 xx 1/8 =1 ` Volume of the atom = ` 4/3 pi r^(3)` volume of the cube = ` a^(3) = ( 2r)^(3) = 8 r^(3)` Fraction occupied = `( 4/3 pi r^(3))/( 8 r^(3) ) = pi/6`

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