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The fraction of thetotal volume occupied by the atoms present in a simple cube is |
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Answer» `pi//4` `=8times 1/8=1` `" VOLUME of the cube"=4//3pir^(3)` `" Volumeof the cube" = a^(3)=(2r)^(3) = 8 r^(3)(therefore a =2r)` `therefore "FRACTION occupied" = (4//3timespir^(3))/(8r^(3)) = pi/6` |
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