1.

The fraction of thetotal volume occupied by the atoms present in a simple cube is

Answer»

`pi//4`
`pi//6`
`pi/3sqrt2`
pi/4sqrt2`

Solution :In a simple cube, NUMBER of atoms/unit cell
`=8times 1/8=1`
`" VOLUME of the cube"=4//3pir^(3)`
`" Volumeof the cube" = a^(3)=(2r)^(3) = 8 r^(3)(therefore a =2r)`
`therefore "FRACTION occupied" = (4//3timespir^(3))/(8r^(3)) = pi/6`


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