The fraction of total volume occupied by the atoms present in a simple cube isA. `(pi)/(6)`B. `(pi)/(3sqrt(2))`C. `(pi)/(4sqrt(2))`D. `(pi)/(4)`

The fraction of total volume occupied by the atoms present in a simple

1.	The fraction of total volume occupied by the atoms present in a simple cube isA. `(pi)/(6)`B. `(pi)/(3sqrt(2))`C. `(pi)/(4sqrt(2))`D. `(pi)/(4)`
Answer» Correct Answer - A P.F.`=("vol. occupied by the atom in a unit cell")/("vol. of unit cell")=((4)/(3)pir^(3))/(a^(3))` For simple unit `a=2r=((4)/(3)pir^(3))/(8r^(3))=(4pi)/(24)=(pi)/(6)`

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The fraction of total volume occupied by the atoms present in a simple cube isA. `(pi)/(6)`B. `(pi)/(3sqrt(2))`C. `(pi)/(4sqrt(2))`D. `(pi)/(4)`

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