The free energy for a reaction having DeltaH=31400 cal. DeltaS=32 cal – InterviewSolution

1.	The free energy for a reaction having DeltaH=31400 cal. DeltaS=32 cal K^(-1)mol^(-1) at 1000^(@)C is
Answer» `-9336` CAL `-7386` cal `-1936` cal `+9336` cal Solution :`DeltaG=DeltaH-TDeltaS=31400-1273xx32` `=31400-40736=-9336` cal.

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