1.

The freezing point (in .^(@)C) of a solution containing 0.1 g of K_(3)[Fe(CN)_(6)] (Mol. Wt. 329) in 100 g of water (K_(f)=1.86 "K Kg mol"^(-1)) is

Answer»

`-2.3xx10^(-2)`
`-5.7xx10^(-2)`
`-5.7xx10^(-3)`
`-1.2xx10^(-2)`

SOLUTION :`Delta T_(f)=ixx K_(f)xx m`
`=4xx1.86xx(0.1)/(329xx0.1)=2.3xx10^(-2)`
`rArr T_(f)=0-2.3xx10^(-2)=-2.3xx10^(-2) .^(@)C`.
`rArr V = 6 ML`.


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