1.

The freezing point of 0.08m NaHSO_(4) is -0.345^(@)C. Calculate the percentage of HSO_(4)^(-1) that transfer a proton to water to form SO_(4)^(-2) ion. K_(f) of H_(2)O=1.86 k "mol"^(-1)kg.

Answer»

Solution :`NaHSO_(4)+H_(2)O(aq)toNa^(+)+H_(3)O^(+)+SO_(4)^(2-)`
`t=0"" 1""0""0""0`
`"at eq. " ""1-ALPHA""alpha""alpha""alpha`
`i=(1+2 alpha)/1`
`DeltaT_(f)=ixxK_(f)xxm`
`0.345=(1+2alpha)xx1.86xx0.08`
So `alpha=0.6591`
% dissociation `=65.92%`


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