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The freezing point of 0.1 M solution of glucose is `-1.86^(@)C`. If an equal volume of 0.3 M glucose solution is added, the freezing point of the mixture will beA. `-7.44^(@)C`B. `-5.58^(@)C`C. `-3.72^(@)C`D. `-2.79^(@)` |
Answer» Correct Answer - c `K_(f) = DeltaT_(f)//M = 1.86//0.1 = 18.6` `0.1xxV + 0.3 V = M_(3)xx2V` or `M_(3) = 0.2` `DeltaT_(f) = 18.6xx0.2 = 3.72^(@)C` `T_(f) = 18.6xx0.2 = 3.72^(@)C` `T_(f) = -3.72^(@)C` |
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