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The freezing point of 0.1 M solution of glucose is `-1.86^(@)C`. If an equal volume of 0.3 M glucose solution is added, the freezing point of the mixture will beA. `-7.44^(@)C`B. `-5.58^(@)C`C. `-3.72^(@)C`D. `-2.79^(@)C` |
Answer» Correct Answer - C Freeing point of mixture is `M_(1)V_(1) + M_(2)V_(2) = M_(3)V_(3)` `K_(f) = Delta T_(f) // m = 1.86 //0.1 = 18.6` `0.1 xx V + 0.3 xx V = M_(3) xx 2V` or `M_(3) = 0.2, Delta T_(f) = 18.6 xx 0.2 = 3.72^(@)` `T_(f) = 3.72^(@) C` |
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