1.

The freezing point of a 0.05 m BaCl_(2) in water ( 100% ionisation) is about (K_(f)=1.86 Km^(-1)) :

Answer»

`-0.279^(@)C`
`-0.558^(@)C`
`-0.093^(@)C`
`-0.186^(@)C`

Solution :`BaCl_(2) hArr Ba^(2)+2Cl^(-), i=3`
`DeltaT_(F)=iK_(f) xx m`
`DeltaT_(f)=3xx1.86 xx 0.05=0.279^(@)C`


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