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The freezing point of a `0.05` molal solution of a non-electrolyte in water is: (`K_(f) = 1.86 "molality"^(-1)`)A. (a) `-1.86^(@)C`B. (b) `-0.93^(@)C`C. (c ) `-0.093^(@)C`D. (d) `0.093^(@)C` |
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Answer» Correct Answer - C `Delta T_(f) = 1.86 xx 0.05 = 0.093`, `:. T_(f) = 0-0.093 = -0.093^(@)C` |
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