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The freezing point of a 1.00 m aqueous solution ofHF is found to be -1.91 ^(@)C. The freezing point constant of water, K1is 1 .86 K kg mol^(-1) The percentage dissociation ofHF at this concentration is |
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Answer» `30%` `I = (Delta T_(f))/(K _(f) xxm ) = (1.91)/(1.86xx1) =1.02` For `HI HARR H ^(+) + I ^(-)` `1- alpha + alpha + alpha =i= 1.027` `1+ alpha =1.02` `alpha = 0.02 or 2.7%` |
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