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The freezing point of a solution containing 18 g of a non-volatile solute dissolved in 200 g of water decreases by 0.93. Find the molecular mass of solute. K_(f) for water is 1.86 K/m.

Answer»


SOLUTION :`W_(B)=18g, W_(A)=0.2"kg", DeltaT_(b)=0.93 K, K_(f)=1.86" K kg mol"^(-1), M_(B)=?`
`M_(B)=(K_(f)xxW_(B))/(DeltaT_(f)xxW_(A))=((1.86" K kg mol"^(-1))xx(18 g))/((0.93 K)xx(0.2" kg"))=180" g mol"^(-1)`.


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