1.

The freezing point of a solution containing 4.8 g of a compound in 60 g of benzene is 4.48. What is the molar mass of the compound ? ( K_(f)=5.1 Km^(-1), freezing point of benzene =5.5^(@)C )

Answer»

200
40
400
256

Solution :`M_(B)=(k_(f)xx1000xxw_(B))/(w_(A) xx DELTA T_(f))=(5.1xx1000xx4.8)/(60xx1.02)=400`


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