1.

The freezing point of a solution containing 4.8 g of a compound in 60 g of benzene is 4.48. What is the molar mass of the compound (K_(f)=5.1 km^(-1)), (freezing point of benzene = 5.5^(@)C)

Answer»

100
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400

Solution :`m=(K_(f)xx1000xxw)/(W XX Delta T_(f))=(5.1xx1000xx4.8)/(60xx1.02)=400`.


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