1.

The freezing point of a solution prepared from 1.25 gm of a non-electrolyte and 20 gm of water is 271.9 K. If molar depression constant is 1.86 Kg K "mole"^(-1), then molar mass of the solute will be

Answer»

`105.7`
`106.7`
`115.3`
`93.9`

SOLUTION :MOLAR mass `=(K_(f)xx1000xx w)/(DELTA T_(f)xx W)=(1.86xx1000xx1.25)/(20xx1.1)`
`=105.68=105.7`.


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