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The freezing point of the aqueous solution of urea is -0.6^(@)C. How much urea should be added to 3 kg water to get such solution ? (K_(f)=1.5^(@)"C Kg. mol"^(-1)) |
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Answer» 72 gram `W=(Delta TXX M xx W_(o))/(K_(f)xx1000)` `therefore W=(0.6xx60xx3000)/(1.5xx1000)=72` gram. |
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