1.

The freezing point of the solution M is -

Answer»

268.7 K
268.5 K
234.2 K
150.9 K

SOLUTION :`"MOLARITY "m=(x_Bxx1000)/((1-x_B)m_A)=(0.1xx1000)/(0.9xx46)=2.415`
`DeltaT=K_"F"xxm=2xx2.415=4.83`
Freezing POINT of solution = 155.7 – 4.83 = 150.9 K.


Discussion

No Comment Found