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The frequency of a light wave in a material is `2xx10^(14)Hz` and wavelength is `5000 Å`. The refractive index of material will beA. `1.40`B. `1.50`C. `3.00`D. `1.33` |
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Answer» Correct Answer - C Velocity of light waves in material is `v=nlamda` ..(i) Refractive index of material is `mu=(c)/(v)` ..(ii) Where `c` is speed of light in vacuum or air. or `mu=(c)/(nlamda)` ..(iii) Given, `n=2xx10^(14)Hz` `lamda=5000 Å = 5000 xx 10^(-10) m`, `c = 3 xx 10^(8) m//s` Hence, from Eq (iii) we get `mu=(3xx10^(8))/(2xx10^(14)xx5000xx10^(-10))=3.00` |
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