1.

The frequency of a particle performing SHM is 12 Hz. Its amplitude is 4 cm. Its initial displacement is 2 cm towards positive extreme position. Its equation for displacement is

Answer»

`x= 0.04 cos(24pit+ (PI)/(6))`
`x= 0.04 sin(24pit)`
`x= 0.04 sin(24pit+ (pi)/(6))`
`x= 0.04 cos(24pit)`

ANSWER :C


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