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The frequency of a particle performing `SHM` is `12Hz`. Its amplitude is `4cm`. Its initial displacement is `2cm` towards positive exterme positions. Its equation for displacement isA. `x = 0.04 cos (24pi t+(pi)/(6))m`B. `x = 0.04sin (24 pit)m`C. `x = 0.04 sin(24pit+(pi)/(6))m`D. `x = 0.04 cos (24 pit)m` |
Answer» Correct Answer - C `x = A sin (omegat +phi)` |
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