The frequency of first line of Balmer series in hydrogen atom is V° .

1.	The frequency of first line of Balmer series in hydrogen atom is V° .The frequency of corresponding let be emitted by singly ionised helium atom is
Answer» Answer: 4v° Explanation: We know v=c/lambda And by the formula , 1/lambda=R(Z^2) (1/n1^2- 1/n2^2) => V°=RC(Z^2) (1/n1^2- 1/n2^2) Here Z= ATOMIC number. For helium aromic number = 2 Therefore, In CASE 1: v=v°, Z=1 So, v°= Rc(1^2) (1/2^2- 1/3^2). [ As it is in the Balmer SERIES, where n1= 2 and n2=3] Case 2: v=x , Z =2 ( for helium) So, x= Rc(2^2)(1/2^2- 1/3^2) Now, from case 1 and 2 we have, V°/x= 1/2^2 => x=4v°

The frequency of first line of Balmer series in hydrogen atom is V° .The frequency of corresponding let be emitted by singly ionised helium atom is

Answer»

Answer:

4v°

Explanation:

We know v=c/lambda

And by the formula ,

1/lambda=R(Z^2) (1/n1^2- 1/n2^2)

=> V°=RC(Z^2) (1/n1^2- 1/n2^2)

Here Z= ATOMIC number.

For helium aromic number = 2

Therefore,

In CASE 1: v=v°, Z=1

So, v°= Rc(1^2) (1/2^2- 1/3^2). [ As it is in the Balmer SERIES, where n1= 2 and n2=3]

Case 2:

v=x , Z =2 ( for helium)

So, x= Rc(2^2)(1/2^2- 1/3^2)

Now, from case 1 and 2 we have,

V°/x= 1/2^2

=> x=4v°