1.

The frequency of light emitted for the transition n=4 to n=2 of He^(+) is equal to the transition in H atom corresponding to which of the following?

Answer»

n=2 to n=1
n=3 to n=2
n=4 to n=3
n=3 to n=1

Solution :`v(H)=v(HE^(+))`
`[RZ^(2)(1/(n_(1)^(2))-1/(n_(2)^(2)))]_(H)=RZ^(2)(1/(n_(1)^(2))-1/(n_(2)^(2)))_(He^(+))`
`1/(n_(1)^(2))-1/(n_(2)^(2))=4(1/4-1/16)`
`1/(n_(1)^(2))-1/(n_(2)^(2))=1/1-1/4`
`:.n_(1)=1` and `n_(2)=2`


Discussion

No Comment Found

Related InterviewSolutions