1.

The frequency of oscillation is ______Hz.A. 0.5B. 2C. 50D. 100

Answer» Correct Answer - A
The number of turns wound over the rod = 200 .
The diameter of the rod , (d) = 10 cm
R = 5cm = 0.5 m
The time taken of wind, (t) = 2s
The length of the wire wound in one second = `("distance")/("time")`
` = (200 xx 2pir)/2= (200 xx 2pixx0.05)/2 = 10 pi m`


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