The frequency of oscillation of a mass m suspended from a spring having force constant k is given by f = Cm^(x)k^(g), where C is a dimensionless quantity. The value of x and y

The frequency of oscillation of a mass m suspended from a spring havin

1.	The frequency of oscillation of a mass m suspended from a spring having force constant k is given by f = Cm^(x)k^(g), where C is a dimensionless quantity. The value of x and y
Answer» `x=(1)/(2),y=(1)/(2)` `x=-(1)/(2),y=-(1)/(2)` `x=(1)/(2),y=-(1)/(2)` `x=-(1)/(2),y=(1)/(2)` Solution :`f=C m^(x)k^(y)[k]=M^(1)L^(0)T^(-2)` Comparing dimensional FORMULA on both sides, `M^(0)L^(0)T^(-1)=M^(x)(M^(1)L^(0)T^(-2))^(y)` `=M^(x)xxM^(y)M^(y)L^(0)T^(-2y)` `M^(0)L^(0)T^(-1)=M^(x+y)L^(0)T^(-2y)` Comparing dimensional formula on both SIDE `0x+y and -1=-2y` `:.y=(1)/(2)So, 0=x+(1)/(2)` `:.x=-(1)/(2)`