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The frequency of oscillation of a mass m suspended by a spring is 'v'. If mass is cut to one fourth then what will be the frequency of oscillation? |
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Answer» SOLUTION :The frequency of OSCILLATION of a mass suspended by a SPRING `V = (1)/(2pi) sqrt((k)/(m))` `therefore v propto (1)/(sqrt(m))` `therefore (v_2)/(v_1)= sqrt((m_1)/(m_2))= sqrt((m_1)/((m_1)/(4)))= sqrt(4) = 2` `therefore v_(2) = 2v""[therefore v_(1) = v]`. |
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