1.

The frequency of oscillations of a mass m suspended by spring is v_(1). If the length of the spring is cut to one- third, the same mass oscillates with frequency v_(2). Determine the value of (v_(2))/(v_(1)).

Answer»

SOLUTION :Let k be the spring constant of FULL spring. Then,
`v_(1)=(1)/(2pi) sqrt((k)/(m)) ""....(1)`
When the spring is cut one- thirdd of its LENGTH, its spring constant k=3k. Now
`v_(2)=(1)/(2pi) sqrt((k')/(m))`
`=(1)/(2pi) sqrt((3k)/(m))`
`:. (v_(2))/(v_(1))= sqrt(3)`


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