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The frequency of vibration of string depends on the length `L` between the nodes, the tension `F` in the string and its mass per unit length `m`. Guess the expression for its frequency from dimensional analysis. |
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Answer» Correct Answer - `(k)/(L)sqrt((F)/(m))` Frequency `prop L^(a)F^(b) (m)^(c)=L^(a)F^(b)((M)/(L))^(c)` `(1)/(T)=kL^(a)(MLT^(-2))^(b)((M)/(L))^(c) " " [krarr"Proporsionality constant"]` `T^(-1)=kL^(a+b-c)M^(b+c)T^(-2c)` On comparing `c=-(1)/(2), b=+(1)/(2),a=1` frequency `(k)/(L)sqrt((F)/(m))` |
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