The friction coefficient between the horizontal surface and each of the block shown in the figure is `0.2`. The collision between the blocks is perfectly elastic. Find the separation between them when they come to rest. (Take `g=10m//s^2`).

The friction coefficient between the horizontal surface and each of th

1.	The friction coefficient between the horizontal surface and each of the block shown in the figure is `0.2`. The collision between the blocks is perfectly elastic. Find the separation between them when they come to rest. (Take `g=10m//s^2`).
Answer» Correct Answer - 5 Velocity of first block before collision `v_(1)^(2)=l^(2)-2(2)xx0.16=1-0.64, v_(1)=0.6m//s` By conservation of momentum `2xx0.6=2v_(1)+4v_(2)` also `v_(2)-v_(1)` for elastic collision It gives `v_(2)=0.4 m//s, v_(1)=-0.2 m//s` Now distance moved after collision `S_(2)=((0.4))/(2xx2)` and `S_(1)=((0.2)^(2))/(2xx2), s=s_(1)+s_(2)=0.05m = 5 cm`.

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The friction coefficient between the horizontal surface and each of the block shown in the figure is `0.2`. The collision between the blocks is perfectly elastic. Find the separation between them when they come to rest. (Take `g=10m//s^2`).

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