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The function .................. |
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Answer» Correct Answer - 2 `x|x|` is differentiable at `x=0` so `(x-2) (x+2) |x-2| |x-1|+ cos|x|` `(x-2) |(x-2)|` is differentiable at `x=2` so `f(x)` is not differentiable at `x=1` |
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