1.

The function ..................

Answer» Correct Answer - 2
`x|x|` is differentiable at `x=0`
so `(x-2) (x+2) |x-2| |x-1|+ cos|x|`
`(x-2) |(x-2)|` is differentiable at `x=2` so `f(x)` is not differentiable at `x=1`


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