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The function `f(x)=1+x(sinx)[cosx], 0ltxlepi//2`, where `[.]` denotes greatest integer functionA. is discontinuous is `(0,pi//2)`B. is strictly decreasing in `(0,pi//2)`C. is strictly increasing in `(0,pi//2)`D. has global maximum value 1 |
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Answer» Correct Answer - D For `0gtxlepi//2,[cosx]=0` Hence `f(x)=1` for all `xepsilon(0,pi//2)`. `f(x)` is continuous on `(0,pi//2)`. This function is neither strictly increasing nor strictly decreasing and its global maximum is 1. |
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