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The function f(x)=x∫−1t(et−1)(t−1)(t−2)3(t−3)5 dt has a maximum value at x=k. If k=cosθ+secθ, then cos6θ+sec6θ is equal to |
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Answer» The function f(x)=x∫−1t(et−1)(t−1)(t−2)3(t−3)5 dt has a maximum value at x=k. If k=cosθ+secθ, then cos6θ+sec6θ is equal to |
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