The function y=f(x) is the solution of dydx+xyx2−1=x4+2x√1−x2 an – InterviewSolution

1.	The function y=f(x) is the solution of dydx+xyx2−1=x4+2x√1−x2 and f(0) = 0, then f(0.5) =
Answer» The function $y = f (x)$ is the solution of $\frac{d y}{d x} + \frac{x y}{x^{2} - 1} = \frac{x^{4} + 2 x}{\sqrt{1 - x^{2}}}$ and f(0) = 0, then f(0.5) =

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