1.

The fundamental frequency of a stretched string is V_(0). If the length is reduced by 35% and tension increased by 69% the fundamental frequency will be

Answer»

`0.2V_(0)`
`0.5V_(0)`
`2.0V_(0)`
`1.6V_(0)`

Solution :`v_(0)=1/(2L)sqrtT/M` Frequency is NEW cond. `V = 1/(2(65% of L))(sqrtT+69%of T)/M`


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