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The fundamental mode of vibration of a stretched string is shown belown Let the fundamental frequency is 45 hz and the length of wire is 87.5 cmif the linear density of wire is 4xx10^(-2)kg m find the tension in the string. |
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Answer» SOLUTION :`v_0` = 45Hz, L = `87xx10^-2m`,`lemda` = `4xx10^-2` V = `1/2l sqrtT/m`.T = 248N |
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