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InterviewSolution
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The galvanometer, in each of the two given circuits deos not show any deflection. Find the ratio of the resistors `R_(1)` and `R_(2)` used in these two circuits. |
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Answer» Current sensitivity of a galvanometer is defined as the deflection in galvanometer per unit current. Its SI unit is Radians/Ampere. For balanced Wheatstone bridge, there will be no deflection in the galvanometer. `(4)/(R_(1))=(6)/(9)" "R_(1)=(4 xx 9)/(6) = 6 Omega`. For the equivalent circuit, when the Wheatstone. bridge is balanced, there will be no deflection in the galvanometer. `(12)/(8)=(6)/(R_(2)) rArr R_(2)=(6 xx 8)/(12) = 4 Omega` `(R_(1))/(R_(2))=(6)/(4)=(3)/(2) rArr 3 : 2`. |
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