The general solution of a differential equation of the type dxdy+P1x=Q

1.	The general solution of a differential equation of the type dxdy+P1x=Q1 is (a) ye∫P1 dy=∫(Q1e∫P1 dy)dy+C (b) ye∫P1 dx=∫(Q1e∫P1 dx)dx+C (c) xe∫P1 dy=∫(Q1e∫P1 dy)dy+C (d) xe∫P1 dx=∫(Q1e∫P1 dx)dx+C
Answer» The general solution of a differential equation of the type $\frac{d x}{d y} + P_{1} x = Q_{1}$ is (a) $y e^{\int P_{1} d y} = \int (Q_{1} e^{\int P_{1} d y}) d y + C$ (b) $y e^{\int P_{1} d x} = \int (Q_{1} e^{\int P_{1} d x}) d x + C$ (c) $x e^{\int P_{1} d y} = \int (Q_{1} e^{\int P_{1} d y}) d y + C$ (d) $x e^{\int P_{1} d x} = \int (Q_{1} e^{\int P_{1} d x}) d x + C$

The general solution of a differential equation of the type dxdy+P1x=Q1 is (a) ye∫P1 dy=∫(Q1e∫P1 dy)dy+C (b) ye∫P1 dx=∫(Q1e∫P1 dx)dx+C (c) xe∫P1 dy=∫(Q1e∫P1 dy)dy+C (d) xe∫P1 dx=∫(Q1e∫P1 dx)dx+C

Answer»

The general solution of a differential equation of the type $\frac{d x}{d y} + P_{1} x = Q_{1}$ is

(a) $y e^{\int P_{1} d y} = \int (Q_{1} e^{\int P_{1} d y}) d y + C$

(b) $y e^{\int P_{1} d x} = \int (Q_{1} e^{\int P_{1} d x}) d x + C$

(d) $x e^{\int P_{1} d x} = \int (Q_{1} e^{\int P_{1} d x}) d x + C$